490x^2-1260+180=0

Solution for 490x^2-1260+180=0 equation:

490x^2-1260+180=0

We add all the numbers together, and all the variables

490x^2-1080=0

a = 490; b = 0; c = -1080;
Δ = b2-4ac
Δ = 02-4·490·(-1080)
Δ = 2116800
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{2116800}=\sqrt{705600*3}=\sqrt{705600}*\sqrt{3}=840\sqrt{3}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-840\sqrt{3}}{2*490}=\frac{0-840\sqrt{3}}{980}
=-\frac{840\sqrt{3}}{980}
=-\frac{6\sqrt{3}}{7}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+840\sqrt{3}}{2*490}=\frac{0+840\sqrt{3}}{980}
=\frac{840\sqrt{3}}{980}
=\frac{6\sqrt{3}}{7}
$